00:01
All right, so step one, we need a graph of 10 sine 2t from 0 to 2 pi.
00:06
So the period 2t is 2 pi over 2, so pi.
00:11
So the graph should just sign looks like this.
00:14
Goes halfway before you get to 2 pi, and then we'll repeat that when you get to 2 pi.
00:24
And so then these, this is at pi over 2, pi.
00:31
3 pi over 2.
00:33
And then the 10 just means that these peaks are 10 and these peaks are negative 10.
00:43
Okay, so where's the motion positive? we just need all the places where this graph is positive.
00:53
So we think, again, v of t is positive.
00:56
And so that happens from 0 to pi over 2.
01:03
These are all the different places lists all when, when.
01:10
So from there and also from pi to 3 pi over 2 and from that's it, okay? and then where is the velocity negative? that would be when the motion is going down or left i guess probably in this problem and so this would be all the others.
01:31
And then we use open parentheses for all these because in between these intervals it's briefly stopped the particle.
01:41
Now, if i want the displacement, i need to add and subtract all the different areas, but in this problem, all of these areas will just cancel...