Question
Divide $\mathrm{y}^{2}+\mathrm{y}-20 / \mathrm{y}-3$ by $\mathrm{y}^{2}-16 / \mathrm{y}^{2}+\mathrm{y}-12$.
Step 1
First, let's factor the numerators and denominators of both fractions: $y^2 + y - 20 = (y + 5)(y - 4)$ $y^2 - 16 = (y + 4)(y - 4)$ $y^2 + y - 12 = (y + 4)(y - 3)$ Now we can rewrite the given expression as: $\frac{(y + 5)(y - 4)}{(y - 3)} \div \frac{(y + 4)(y Show more…
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