Step 1:
We are given that the difference in binding energy $\Delta B$ is given by the formula $\Delta B = \frac{1}{8} \frac{3kQ_1^2}{5R} - \frac{1}{8} \frac{3kQ_2^2}{5R}$, where $Q_1$ and $Q_2$ are the charges of the two nuclei, $k$ is Coulomb's constant, and $R$
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