00:01
In this problem, you have hot water flowing out of the tap at a rate of 9 .46 liter per minute.
00:10
And the water is heated up by an on -kind -of -size heater with some unknown power, and we need to find that power.
00:21
So, and the water is heat up from 10 degrees celsius to 49 degrees celsius, which amounts to a change in temperature of 39 degrees.
00:32
Degrees celsius, which is equal to 39 degrees kelvin.
00:38
And so we need to find the power of the heater.
00:44
We can do this by, you know, considering how much water flowing out of the top every one minute.
00:52
So every one minute you have 9 .46 liter of water, liters of water flowing out of the tap.
01:00
And so using this equation, q equals to m, c times delta t, you can compute the amount of heat needed to be transferred to the water every minute...