00:01
So looking at this question, we're going to be finding the concentration of hf.
00:08
So i'm writing out the reaction here, which is h2 plus f2, goes to 2hf.
00:15
And the k -eq is 2 .1 times 10 to the 3.
00:22
Concentration of both h and f is 0 .0021.
00:27
So first we're going to write out the k -e -q.
00:33
So we're going to use the products as the numerator.
00:43
So h -f, and then because there's two mole of that, that's to the second power, over h2 times 2.
00:56
So looking in the values that we have, we have 2 .1 times 10 to the 3 is equal to x squared over 0 .021 times 0 .021.
01:15
Simplifying that, we're going to multiply 0 .021 times 0 .01, times 0 .021, which gives us 4 .41 times 10 to the negative 6...