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Draw a curve similar to that shown in Figure 14.23 for a series of solutions of $\mathrm{NH}_{3}$ . Plot $\left[\mathrm{OH}^{-}\right]$ on the vertical axis and the total concentration of $\mathrm{NH}_{3}$ (bonized and nonionized $\mathrm{NH}_{3}$ molecules) on the horizontal axis. Let the total concentration of $\mathrm{NH}_{3}$ vary from $1 \times 10^{-10} \mathrm{M}$ to $1 \times 10^{-2} \mathrm{M} .$

3.90

Chemistry 102

Chapter 14

Acid-Base Equilibria

Liquids

University of Central Florida

Brown University

University of Toronto

Lectures

03:07

A liquid is a nearly incom…

04:38

A liquid is a state of mat…

01:35

For the reaction$$\mat…

00:54

At $450^{\circ} \mathrm{C}…

02:07

00:22

In the presence of $\mathr…

01:09

An equilibrium mixture of …

01:10

Consider the reaction.…

03:08

Calculate the equilibrium …

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02:26

Consider an initial mixtur…

02:31

01:59

At $25^{\circ} \mathrm{C},…

01:44

What is the value of the e…

01:13

Consider the equilibrium r…

03:38

At $218^{\circ} \mathrm{C}…

01:23

Consider the reaction:…

03:00

Using the dissociation con…

05:07

01:55

Analysis of the gases in a…

02:36

The pH of a solution of $\…

the tight creation go with a graph that relates the changing pH. Often acidic or basic solution. So the volume at it tightening the characteristic off iteration go are dependent on the specific solution being titrate. The pH off the solution at Equal villains point may be greater than equal to or less than seven. The reaction is given us follow, along with the equilibrium expression where K B is equal to 1.8 into 10 minutes of our minus five. The initial and equally grim concentration for this system can be summarized in the given tabular form. This shows the initial concern tree concentrations changing concentration along with equilibrium concentration. From this table, we can substitute the value to find the KP, which turns out to be 1.8 into tended super minus five. Now for part for B, which is equal to concentration off industry. It is then into my attend Ray's tow bar minus toe. Assuming that ex lies in between the concentration off industry, Onda was negative. As for so we can better mind the value of K P, which is X rays to power toe divided by 10 Ray's tow bar minus two we can solve for X, which is equal to concentration off which negative vines That is, 4.24 into Henry's to bar minus four upon test testing the assumption the value is 4.2% off 10 day super minus seven. Thus, the assumption is valid the provided that, uh, provide accord Gatica question given us below. Upon simplifying the corner integration, we can substitute one for a 1.8 into 10 days. Super minus phi for B at 1.8 into 10 days, super minus eight. Foresee, We can calculate the value off X by just substituting in the values External Toby 1.3 in 10 days super minus four. Therefore, X is equal to concentration off west negative wine, which is 1.3 into 10 days or minus for em. We can do to mine the huge that this negative log off hydroxide iron hydroxide value the beauty JJ Uh, the Buick is three point 90 we can do. Don't mind the beer we can deter mined the concentration off. View it from 14 minus de Gunson from Come on. Ben is not working from 14 minus the value off B itch. The value off huge turns out to be 10.10 Similarly, in that way, the pH off each concentration is determined on listed as in the folding table. Now, using the above values, we can plot the graph off huge against the total concentration off industry. Let me make the graph. We have zero one two my six. And we have the U. S. Value bearing from 2.0 No eat y zero. We have three over here. We have four. We have five six soon. If you make the graph, it starts at nearby between one and two. It goes both upto 11 6 We're it gets constant.

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