00:01
In this question we've been given methanol and we want to determine the heat cap, that is a blood of t against q.
00:11
So the main formula that we're going to be using here is q is equal to mcp delta t.
00:18
This is the general formula that we're going to be using.
00:21
So now looking at a transition from 170 to 176 kelvin, that is the melting point, the melting point of methanol.
00:31
We're going to have a q being equal to 1 mole of methanol multiplied by the cp, which is 105, multiplied by the change in temperature from 1702 -176, which is equal to 6 kelvin.
00:49
So our q here is going to be equal to 1 multiplied by 106 multiplied by 6.
00:55
So this is going to be equal to 630 joules which is equal to 0 .63 kilochols.
01:04
Now moving on.
01:08
Now we know we are now changing phase, changing phase and this process occurs at a constant temperature.
01:19
So all we have to do to determine our q, this is n multiplied by the enthalpy change of that change in phase, which is the endelope change of few...