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In this problem, you are asked to draw the lewis structure of four compounds.
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A, nh2, cl, b, cl2o, c, f -cn minus, and d, h -of.
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The problem also asks you to determine the electron pair and molecular geometry of each of the molecules.
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So let's start with part a.
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The first step in determining a lewis structure is adding up the number of valence electrons you have.
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Nitrogen has five valence electrons.
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Hydrogen has one valence electron, and we have two hydrogens.
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And chlorine has seven valence electrons.
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Add this up, and you get a total of 14 valence electrons.
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In this case, the central atom is most likely going to be nitrogen.
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Hydrogen cannot be the central atom, and between nitrogen and chlorine, nitrogen has the least negative electron affinity.
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So we'll connect the central atom to the chlorine and the two hydrogens using single bonds.
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Then we fill in what remains with lone pairs until the octet rule is satisfied.
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When you count up the number of electrons, you see that there are indeed 14.
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So this lewis structure is correct.
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Now to determine the geometry.
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Nitrogen has four electron groups coming off of it.
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So the electron pairs will arrange themselves in the tetrahedral structure like this.
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This hydrogen going forwards and this hydrogen going backwards.
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So clearly, the electron pair geometry is tetrahedral.
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Ignoring lone pairs, you can see that the molecular geometry, which just involves the four atoms, is trigonal pyramidal.
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Now let's move on to part b.
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We have cl2o as our compound for part b.
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So to draw the lewis structure, let's start by adding up the valence electrons.
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Chlorine has seven valence electrons, and we have two chlorines, and oxygen has six valence electrons.
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Therefore, we have a total of 20 valence electrons that will appear in the lulo.
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Structure.
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Out of these two elements, chlorine and oxygen, oxygen has the least negative electron affinity, so that will be our central atom, and we'll connect it to the two chlorines using single bonds.
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To satisfy the actette rule, we'll add lone pairs around each of the atoms.
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When we count the number of electrons that are in the structure, we have 20 valence electrons, which matches up with the amount we determined earlier.
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So, this is the correct lewis structure for this compound.
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Now let's look at the geometry.
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The central atom, once again, has four electron groups coming off of it, two bonds and two lone pairs.
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And in space, they will arrange themselves like this, with one chlorine coming forwards, and one chlorine going backwards...