00:01
This is the answer to chapter 16, problem number 45 from the smith organic chemistry textbook.
00:09
And we're asked to draw a stepwise mechanism for this reaction.
00:15
And so it is a hydrobromination of one of these two alkenes, and it's taking place under radical conditions.
00:27
And so we learned this reaction in the previous chapter, chapter 15.
00:32
And so hopefully you remember that when an alkenes is treated with hbr under radical conditions, the bromine is going to end up on the carbon with more hydrogens.
00:44
So this is going to be an anti -marcov -nakov type reaction.
00:50
And so the mechanism is going to look like this.
00:54
So first, we're going to have our radical initiator species.
01:00
So our peroxide species.
01:04
And to begin with, the oxygen -oxygen bond is going to cleave homilidically.
01:13
So that's where our radical comes from.
01:29
Okay, so we now have this or oxygen radical species.
01:35
And that is going to be what interacts with our first equivalent of hbr.
01:50
And so we end up having this happen.
02:05
So we have the alcohol here now.
02:08
And we also have a bromine radical.
02:20
And so it's going to be this bromine radical that now actually adds to our starting material.
02:32
So i'll draw the starting material just right here.
02:42
Oops.
02:44
Oh, wait, no, that's right.
02:44
One, two, three, four, two, three, four.
02:47
Yeah, okay...