00:02
This is the answer to chapter 24, problem number 69, from the smith organic chemistry textbook.
00:10
This problem asks us to draw a stepwise mechanism for this reaction, which was used in the synthesis of a drug for high cholesterol.
00:21
Okay, and so this is just going to be a pretty straightforward enolate formation, and then the enolate is going to act as a nucleophile.
00:36
So the first thing that's going to happen is going to be deprotonation of this alpha proton by lda.
01:01
Okay, so once this deprotonation occurs, we have the enolate.
01:07
And now that enolate, oh, and i should mention this, right? so i am abbreviating this large molecule with two arrow groups in it the way that i've drawn at the top of the screen here.
01:21
So that is where this molecule comes in.
01:27
So ar and ar prime to denote the two arrow groups.
01:32
It's a pretty common abbreviation.
01:36
And so the attack is going to happen here.
01:44
These electrons will go here to the nitrogen.
01:49
And so after that step, we are here.
02:02
So i'm also going to draw this in the confirmation that makes it sort of easy to see how we get to our final product.
02:10
It's always a good idea to do as well.
02:29
Okay.
02:31
The nitrogen has two lone pairs, and so a negative charge.
02:37
And so it is now going to be able to attack this carbonyl right here...