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This is the answer to chapter 23, problem number 59, from the smith organic chemistry textbook.
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This problem asks us to draw a stepwise mechanism showing how two alkalation products are formed in the following reaction.
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Okay.
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And so basically what we have here is the lda, the diacopropylamide is going to look.
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Like what i've drawn here.
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And so that is going to grab this proton, and the electrons will go to this carbon.
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And so our major intermediate here, oops, let's try that again.
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Okay.
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So our intermediate here, the main intermediate in this reaction, is going to be this one.
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And so we have a loan pair, and a negative charge here now.
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And one thing that can happen is the direct alkalation.
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So have our methyl iodide.
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This lone pair can grab the methyl group.
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And so when that happens, we end up with the one product.
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However, we can also get rearrangement...