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We are asked to draw structures of the following compounds.
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The first is 1 -2 -dye -chlorobenzene.
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So benzene is a 6 -carbons ring with alternating double and single bonds.
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And 1 -2 indicates the position.
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We know dye is 2.
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Chloro is chlorine.
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So put 1 here, and then 2, right there.
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The next one is 1 -3 -dymethyl benzene.
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So again, benzene.
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Methyl is the derivative.
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Of methane, which is just one carbon.
00:44
So we have ch3.
00:52
So one there, and then two, three.
00:58
Another one is three nitrofenal, and phenol is just the benzene ring with an oh attached to it.
01:11
So one, two, three.
01:14
And nitro is just n .o2...