00:01
So in this problem, we are going to make structures for the specified compounds.
00:08
Our first compound is going to be two, methyl, pentanyl.
00:16
So we're going to have a chain of five carbons.
00:25
And then on one end, we're going to have an aldehyde, so a terminal carbonyl group.
00:35
And then on the second carbon, pass that aldehyde group, we are going to have a methyl group.
00:42
Group.
00:43
So this is two methyl pentanil.
00:53
In our second compound, we are going to draw three hydroxybutanic acid.
01:05
This compound has a parent carbon chain of four, and then the oic acid indicates that we will have a hydroxy group and a carbonyl group, making up the acid group, and then on the third carbon, from that acid group, we are going to have hydroxy group, which is oh.
01:34
So this is three hydroxy butinoic acid...