00:01
So let's go over how we would do this.
00:02
So for the first one for ozone, we have three oxygens.
00:08
So the double bond will alternate between one oxygen and the other.
00:13
So it will look something like this.
00:17
So let's calculate the final charge.
00:19
The formula is valance electrons on the atom minus non -bonding electrons on the atom minus spot, bonding electrons divided by two.
00:27
Let's look at how we would do that for the singly bonded oxygen.
00:31
We're looking at this one.
00:32
So the vance electrons is 6 because it is in group 6a or 16.
00:38
Subtract non -bonding.
00:39
If you count the dots, there are 6.
00:42
Then the number of electrons in bonds will be 2 because we have one bond.
00:46
Each bond has 2 electrons.
00:47
So if 2 divided by 2 is negative 1.
00:49
Double -bonded oxygen would be 6 minus 4 minus.
00:55
And in the double bond, we have 4 electrons divided by 2 and then we have 0.
00:59
So the middle oxygen, we're going to do the same thing.
01:02
So 6 minus 2 minus and there are three bonds to it.
01:07
So there are six bonding electrons divided by 2 and that equals 1.
01:11
So then we're going to do the same thing for the next one.
01:13
This is sulfur dioxide.
01:15
Sulfur dioxide just has the double bond alternating between the sulfur and oxygen on the left and the one on the right.
01:23
So then we'll just apply this formula on this as well.
01:27
So balance electrons and sulfur is 6 minus 2 non -bonding minus 6 in the bonds divided by 2...