00:02
Hi, in this problem, we are given a seven carbon compound.
00:06
We have to make all the possible skeletons with the given conditions.
00:12
The first one is a six carbon chain and one double bond.
00:16
So in this case, we will write down the skeletal structures with total seven carbon atoms where the compound has a six carbon chain and one double bond present.
00:27
So let's start with the skeleton structures.
00:30
The first one is having this structure where one carbon atom is present as substitute bonded to this double bonded carbon atom.
00:43
Another structure possible with the same number of atoms is this where the substituted carbon is the third one.
00:57
Then we have this structure where the substitute is present at this carbon atom.
01:09
One more structure we can make and substitute carbon is present at this.
01:19
The next one is this structure where the double bone is present between second and the third carbon atom and substitution is here.
01:34
Then we can make this structure with the same kind of atoms.
01:40
And the substituted carbon is this carbon.
01:47
In the structure is this one.
01:54
One more structure is this one.
02:02
Then we can have more structures with the same kind of arrangement.
02:08
That is double bone is now shifted between carbon 3 and carbon 4 and the substitutant is present here.
02:22
One more structure where we can write the subsequent here and we can have one more structure with this kind of possible arrangement.
02:41
So all these are the skeletal structures for the compound having seven carbon atom where the chain is of six carbon atom and one double bond is present in the compound.
02:54
Then we have to make the structures for a five carbon chain.
02:58
With one double bond.
03:01
So in this, the two carbon atoms will be present as substituent...