00:01
So the difficult thing about this question is that ask us to draw the more like your orbital diagram for hcl, but it doesn't give us a lot of hints on how we need to do that.
00:11
So here is hydrogen's 1s orbital, and for corrine, it has the 3p, which are fairly similar in energy, and it has the 3s, which is much lower.
00:28
So because this 3s is so much lower in energy, it's going to be non -bonding.
00:33
It's going to just form an orbital down here.
00:39
And the hydrogen is going to choose to mix with one of these p orbitals to form a sigma and a sigma star.
00:53
The star indicates that it's anti -bonding.
00:56
And then these other two p -orbitales that have interacted, they are also going to be non -bonding p orbitals.
01:04
So now when we fill in the electrons, hydrogen has one.
01:07
Quarian has one, two, three, four, five, six, seven.
01:18
So we've got eight total electrons...