00:01
For problem number 13, it's the same as problem number 12, and also problems number 3 and 4 in this section.
00:14
So the first thing that we need to do is graph our coordinates, l -m -n -p.
00:19
They want us to identify what the polygon is, and then find the area and perimeter of the shape.
00:25
So the first thing that we need to do is graph l, so that is 7 -5, 1, 2, and then up 5, that is l.
00:38
M is 5 -0, n is 35, and p is 5 -10.
01:02
So what we look to have is a diamond, rhombus, one of the two.
01:15
So the way that we can determine what this shape actually is, is by finding the sides, find the distance of the points of the sides, finding the perimeters.
01:29
Oh my gosh, you have to laugh at yourself sometimes.
01:32
Finding the side links.
01:36
So in order to do this, we need to use the distance formula.
01:39
It doesn't matter what points you call one and two.
01:42
Our distance formula is, of course, d equals the square root.
01:49
I will actually write this down here.
01:52
D equals the square root, x1 minus x2 squared, plus y1 minus y2 squared.
02:04
So the first distance that i want to try to find is lm.
02:11
So lm, i'm going to let lb .1, mb .2, so 7 minus 5 squared, plus 5 minus 0 squared.
02:29
Now when i plug that into my calculator, i will get lm is equal to 5 .39.
02:42
So lm 5 .39.
02:53
Now of course this is not only to classify our shape, but this is also to help us find the perimeter.
02:58
So now that we have lm, we can go and find pl.
03:08
So pl with that same formula, i'm going to let point p be 1, l b2, so 5 minus 7 squared, plus 10 minus 5 squared.
03:25
Plug that into my calculator and i will get pl equals 5 .39...