00:01
In this problem, we are going to discuss isomers with the formula c7h16.
00:10
Because we are working with so many different atoms, i am going to convert the structures into line structures.
00:17
So the is isomer i have on the left is en -hptane, and its corresponding formula would be written out would be the compound on the right.
00:29
So i'm going to use line structures for this problem.
00:33
And heptane could be used as the first isomer, but i'm going to draw three separate compounds.
00:40
So remember that structural isomers have the same number and ratio of atoms.
00:47
It will have seven carbon atoms and 16 hydrogens, but the orders of the bonds will be rearranged.
00:54
So in our first isomer, i'm going to remove a carbon from the end of the molecule and put it on the second carbon.
01:04
The systematic name for this would be 2 methyl hexane.
01:18
Remember to start numbering the chain closest to the side of the first substituent.
01:24
I got my systematic name by first numbering the chain, which i knew had six carbons, and noting that the methyl group was on the second carbon.
01:34
Let's draw another isomer using the same tactic...