00:01
Here the question is, draw an even mechanism of the following reaction and at the same time draw the structure of the transition state for each.
00:14
Even mechanism that means elimination unimolecular.
00:19
Reaction is taking place in two steps.
00:22
So step one should be formation of carbonium ion and breaking of carbon -cl bond.
00:44
So here the reaction should be ch3 2 times c, c, cl, ch2, ch3.
01:08
This is the alkalihylidical and breaking of carbon chlorine bond and by that carbonium ion is formed.
01:40
This is the carbonium ion is found and cl is removed.
01:47
So in case of transition state what happens the structure should be ch3 c, c, ch3, breaking of this bond, chlorine, single bond, ch2 and ch3...