00:01
Okay.
00:03
Lose dot structure for tellurium, dichloride, we'll count up the total number of valence electrons.
00:12
Tullium has six, and then we've got seven for each chlorine, and there are two chlorine, so that's a total of 20 valence electrons.
00:21
So we'll bond the chlorines to the tellurium, use up one, two, three, four valence electrons.
00:30
Satisfy the octet for chlorine.
00:31
Put six more around it and then six more around the other chlorine.
00:36
So that's now a total of 16.
00:37
We've got four valence electrons left.
00:40
We can put two pairs on tellurium so it now has an octet also.
00:48
Then we'll look at hydrogen iodide.
00:51
It has a total of eight valence electrons, one from hydrogen, seven from iodine.
00:56
So we'll bond the two together.
00:59
That will give us six valence electrons left over, which we can put around iodine.
01:03
Iodine to satisfy the octet.
01:08
Then here we have arsenic three bromide or arsenic tribromide.
01:17
Then we will count up the number of valence electrons.
01:20
We've got five from arsenic, we've got seven from bromine.
01:23
There are three of them given us a total of 26...