00:01
Okay, so we're given the formula c6h12 and we need to draw loose structures and identify the three structural isomers that could come from this formula.
00:12
So i'm going to begin with a just chain.
00:17
So from the formula, we know that we have to have a double bond.
00:21
So i'm going to do a c, double bond, c.
00:31
And we need five different carbons here.
00:42
I'm just going to draw my h's.
00:52
It says 1h, and then this has 2.
00:58
Okay, so this has the formula, c6, h12, and we know that this is a chiro molecule because of this carbon right here, which is attached to four different, or three different groups.
01:14
There's no fourth group.
01:15
So this is a chiral molecule.
01:21
So we're going to draw our next isomer.
01:22
For this one, i'm going to draw a ring...