00:01
Let's discuss the design question.
00:03
The question is draw line structures for the following alkenes, which can exist as cistrans isomers, for those that can draw both isomers.
00:18
First part is two methyl, two methyl, two in.
00:38
And next one is part b is hept, hept three in.
00:51
And part c is 3 -4, dye -methyl, hex, 3 -in.
01:17
So here, line structure for compound a is.
01:25
Here we have oct chain containing 8 carbon atoms.
01:31
2, methyl, 1, 2, 3, 4, 5, 6, 7, 8.
01:38
So here double one present and methyl group attach on carbon position number two.
01:47
So this is two methyl oct two in.
01:50
And next one is part b.
02:04
This is having seven carbon atoms, chain containing seven carbon atoms.
02:09
So it will be one, two, three, four, five, six, seven, seven, hip three in...