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This is the answer to chapter 20, problem number two from the mcmurray organic chemistry textbook.
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This problem is sort of the opposite of problem number one.
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So in this problem, we are given six iupac names and asked to draw corresponding structures.
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Okay.
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And so for a, the iupac name that we're given is 23 dimethyl hexinoic acid.
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Okay, and so we should start with the base chain here.
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So hexanoic acid.
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So it's going to be a derivative of hexane.
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So one, two, three, four, five, six.
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So six carbons are carboxylic acid here.
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And so, of course, that's going to be carbon number one, the carbon with the with the carboxylic acid.
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And so now we need to put methyl groups at carbons two and three.
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So if the carboxylic acid carbon is carbon number one.
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The very next carbon would be carbon number two.
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And then the carbon after that would be carbon number three.
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Okay.
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And so there's our iupac structure, or there's our structure for the iupac name, 23 dimethyl hexanelhexinoag acid.
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Okay.
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And so the rest of the problem is going to follow the same pattern.
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So for part b, we have four methyl methyl.
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Pentanoic acid.
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So pentanoic acid.
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So this is going to be a derivative of pentane.
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So one, two, three, four, five.
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We'll put our carboxylic acid here.
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And so this would now be carbon number one, the carboxylic acid.
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And so we need to put a methyl group at carbon number four.
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So one, two, three, four.
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This would be carbon four.
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There's our methyl group.
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And so there is four methanol pentanoic acid.
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Okay.
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For part c, we're given trans 1 -2 cyclobutane di -carboxylic acid.
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Okay, so from that, we should get that the base structure here is going to be a cyclobutane.
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So let's start by drawing our cyclobutane.
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Then we're told trans 1 -2 di -carboxylic acid.
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Okay, so there are two carboxylic acids, and their stereochemistries are opposite one another.
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So let's put one here on the wedge, and then we should put the other here, because it's 1 -2 di -carboxylic acid.
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So we'll put the other one here on the dash.
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Okay, so there we go.
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Trans 1 -2 cyclobutane di -carboxylic acid.
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Okay, so for part d, we have ortho -hydroxybenzoic acid.
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Okay, so this is a benzoic acid derivative.
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So the first thing that we should draw should be the benzene ring.
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Let's draw that.
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And then it's a benzoic acid derivative...