00:01
Okay, so we're drawing structures for problem 59.
00:05
So let's just go for it, starting with part a.
00:08
We got sist2 hexene.
00:10
So hexene, meaning we have six carbons, and 2 and e and e means we have our double bond on carbon 2.
00:21
Okay, so i actually want to start drawing this with carbon 2, having the double bond with carbon 3, right? and it says cis, meaning our hydrogens would be on the same side or our carbons connected to carbons 3 and 4, or 2 and 3, sorry.
00:44
This would be carbon 2 and this would be carbon 3.
00:52
Okay, so cis, meaning our carbons connected to it would be on the same side as well as our hydrogens, right? so if this is carbon 2, meaning we're going to have carbon 1 connected to it.
01:07
Okay, so this is carbon 1.
01:10
And then we're going to have that carbon 4 connected to it as well.
01:18
Okay, so that's what we mean by cis.
01:22
They're going to be on the same side, and the same is true for the hydrogens.
01:29
Okay.
01:30
So this carbon is going to have hydrogen.
01:32
This is going to have a hydrogen and they're going to be on the same side okay so carbon one would have three hydrogens connected to it that because we've pretty much gone over the important part on this molecule so everything that we're going to do here is just filling up those carbons and hydrogens that we have left okay all right so we got carbon four and this is most likely going to be ch2, right? and then we got carbon 5.
02:08
And finally we have carbon 6, which will be a ch3.
02:15
Okay.
02:16
So there we go.
02:17
That's our cystuhexene.
02:21
Moving on to part b.
02:23
We got two methyl three hexene...