00:01
All right, problem 53.
00:04
We are drawing structures, and as you would probably notice by now, they're all cyclic structures, okay? and the reason that i have is cyclic structures pre -drawn below is because i'm not very good at drawing polygons, so hopefully you are.
00:21
But there you have it.
00:23
I have our cyclic structures pre -drawn.
00:28
So let's just go for it.
00:30
Right.
00:31
I'm starting with part a here.
00:33
Part a.
00:35
Part a says cyclo octane.
00:38
Okay.
00:39
So that just means cyclo, meaning you have a ring and octane you mean, that means you have eight carbons.
00:48
Okay.
00:48
So eight carbons in a ring would give you an octagon, right? so outside of chemical or chemistry context, that's called an octagon.
00:59
So you're just going to have to draw an octagon.
01:01
Octagon, okay, which is what i have here in part a.
01:05
So i have a cyclic structure with one, two, three, four, five, six, seven, eight carbons in it, okay? so that's pretty much it for part a.
01:18
Part b, part b is a little more complicated.
01:23
We have, we have function groups now attached to it, right? we got one -one dimethyl cyclopentane, okay.
01:31
So, so pentane means we have five carbons and cyclo means they are in a ring.
01:37
Hence, this pentagon that i have right here on the right side.
01:45
And then we have 1 -1 -dymethyl.
01:50
1 -1 -dymethyl means we have two methyl groups, and both of them are on carbon 1.
01:58
So at this point, you're assigning non -ethyl groups.
02:04
Numbers to carbons and it's arbitrary, right? so you could use any of these carbons as your carbon one.
02:12
So i'll just, i'll just choose this carbon right here.
02:15
Okay.
02:17
So i'll choose that.
02:19
And there are two methyl groups attached to this carbon.
02:23
So i'll go ahead and add those methyl groups...