00:02
Solving problem 3 of chapter 15.
00:09
Draw structures corresponding to the following are upac names.
00:15
Parabromchlorobenzine, parabromatololin, metachloroanilin, 1 -chloro -3 -5 dimethyl benzene.
00:25
So let's start from the first one.
00:28
The name is para -bromochlorobenzine.
00:43
Okay.
00:45
So we know that the principal group is going to be in a benzene.
00:52
So let's start drawing a benzene ring.
00:55
Okay.
00:56
Then we know that it has two different substituent, and they are in paraposition between each other.
01:05
So paraposition means on two opposite carbons.
01:09
One of the substituent is a bromo.
01:12
So let's start just putting a bromo in here.
01:15
Since it's the first one we can just pick whatever carbon we want.
01:20
The second substituent is a chloro atom and we know that with respect to the bromine has to be on the opposite carbon.
01:28
So it's going to be in here.
01:33
Okay, the second molecule is the para -bromotolwin.
01:44
Parabromo -tolwin.
01:50
Okay, so from table 15 .1 we know that toluwine.
01:55
Molecule is a benzene ring with a methyl group.
02:05
Okay.
02:07
So this one is the tall wind.
02:09
And then we know that in para position, so it's going to be in para compared to this methyl substituent, we have a bromine.
02:19
So para again it means on the opposite carbon atom on the benzene ring.
02:25
So in here we will have a bromine...