Draw structures corresponding to the following names: (a) 2,4 -Dimethylheptan- 2 -ol (b) 2,2 -Di

step 1 So let's discuss the design question. The question is draw structures corresponding to the follo

Draw structures corresponding to the following names: (a)...

Key Concepts

Chain and Ring Numbering

Proper numbering of the carbon atoms in acyclic chains or cyclic rings is essential. This involves choosing the numbering direction that gives substituents and functional groups the lowest possible numbers, thereby dictating how the compound is systematically described.

Substituent Identification

Substituents like methyl, ethyl, and methoxy groups are noted in the compound's name with their respective locants. Understanding how these groups attach to the main structure and influence the overall properties of the molecule is key to drawing the correct structure.

IUPAC Nomenclature

This is the systematic method used to name organic compounds. It involves identifying the longest carbon chain or base structure, assigning locants to the principal functional groups, and naming substituents. The process ensures that each compound’s name uniquely represents its structure so chemists can deduce structural information from the name.

Functional Group Identification

Identifying functional groups such as alcohols (-OH) and diols is a crucial step. Recognizing these groups and their positions within the molecule helps in assigning the correct suffixes and locants in accordance with IUPAC rules.

Transcript

00:01 So let's discuss the design question.

00:03 The question is draw structures corresponding to the following names.

00:09 Here, name given in part 8, 24 dimethyl heptane to all.

00:15 This is type of alcohol.

00:16 24 dimethyl, heptane to all.

00:20 So first we will draw the longest chain containing 7.

00:24 Heptane means heptamine 7, 7 carbon atoms.

00:29 1, 2, 3, 4, 5, 6, and 7 and now we will add the substitute event on position 24 and 2 4 here 1 2 3 this is carbon number 2 and this is 4 here will attach the substitute methyl di -methyl c is 3 same substituent attached on different position and here we have attached the 2 -0 here hydroxyl group attached and now we will add hydrogens according to the valency of carbon.

01:03 Carbon has four valence electrons so here we'll add three hydrogens and here we will add two hydrogens and here two and here one and here two and here we'll add no hydrogen zero hydrogen here and with this carbon and one two three four it valence is complete and c h3 so this is the structure for the given name and the question and next part b is 2 -2 -dythyl cyclohexanol.

01:40 So this is cyclic form of alcohol.

01:42 2 -2 -di -ethyl substitute is ethyl group and position 2.

01:48 And so this will be, we will draw the cyclic form and here we will attach hydroxyl and name is hexanol and position 1 and here 2 -2 -diethyl.

02:06 This is ch2, ch3, and ch2, this is ch3.

02:15 And this is 2 -2, this is 1, 2, 3, 4, 5, 6, 2, 2, diethyl cycelohexanol in position 1.

02:25 O .h group attached.

02:27 And next is in part c.

02:32 Name given here is 5 ethyl, 5 methyl methyl, hepdine 1 -0.

02:38 So it will be structure will be we will draw 5 methyl heptane we will draw in part c just a 5ethyl 5 methyl peptine 1 all we will draw the carbon containing a chain containing 7 carbon atoms 1 2 3 4 5 6 and 7 and now we will attach the substituent on position 5 we will attach on position 5 1 2 3 4 5 here we will attach methyl methyl and ethyl c2h 5 and this is here we will attach on position 1 hydroxyl group attached so now we will 8 hydrogens here ch 3 and ch2 this is complete in ch2 ch2 and ch2 and ch2 and ch2 and here we will 8 1 2 and here we will add ch2 so this is 5 ethyl 5 methyl 5 methyl heptan 1 all and part d is the party is 4 ethyl hexane 2 all we'll draw the chain containing 5 carbon atoms 4 ethyl hexane 2 all chain containing 6 carbon atoms here hex mean 6.

04:29 And here now we will add the substituent 3 and 4 ethyl hexane to all.

04:35 1, 2, 3, 4.

04:37 Here we will attach here 4 ethyl hexane to all...

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