00:01
Solving problem 19 of chapter 5.
00:04
Draw the corresponding structure corresponding to the following names.
00:09
So let's start from the first one.
00:12
The name is 3.
00:15
Metal, 1, 2, benzene dynamine.
00:30
So we see there is a benzene, so we start drawing a benzene ring.
00:37
Then we know that in position 1 and 2, we have 2.
00:43
Because we have the suffix d amine and h2 so we have position one let's select this one we have an h2 and we have another of the same group in position 2 so we are going to number the carbon of the benzene ring in this way 1 2 3 4 5 and 6 so 1 and 2 are already occupied but a diamine in position 3 we have a metal so we have a metil so we we add in position 3, a metal.
01:21
Ok.
01:23
Then we have orth amino benzoic acid.
01:39
So we start drawing a benzene.
01:46
Then we know that we have two substituent, and they are in order to each other...