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Problem 9 .19 asks us to draw the compounds below.
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We'll start with compound a.
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3 -3 -dymethyl 4 octine.
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Notice that the parent chain is 8 carbons with a triple bond on carbon 4, so we'll start by drawing that.
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Now we'll add the two methyl groups on the third carbon.
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This completes compound a.
00:46
Now we'll look at compound b, which has a parent chain of decadriene with the triple bonds on carbons 1, 6, and 8.
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Now we'll add the ethyl group on carbon 3, so this carbon, and then we'll draw the methyl group on carbon 5.
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This is compound b.
01:33
Now c has the parent chain of 3 hexine, so we'll begin by drawing that.
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And then it has methyl groups on carbons 2, 2 methylmethyl groups on carbons 2, and 2 on carbon.
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5 and this is 225 tetamethyl 3 hexine.
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Now for question d.
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Question d has a cyclo -deckine, so we'll start by drawing that.
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And remember when counting, they count from the beginning of the triple bond towards the second end of the triple bond.
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So with two methyl groups on carbons 3 and 4, we will count clockwise.
03:10
And then after add in the methyl groups.
03:16
And this is 3 -4 dimethyl cyclodecine...