00:01
For part a, we have s -1 -bromo, 1 chlorobutane.
00:04
So i like to work backwards.
00:06
Butane means that our parent chain has four carbons.
00:10
So i have 1, 2, 3, 4.
00:18
And on carbon 1, we have a bromine and a chlorine.
00:23
And we have to make sure that that has us configuration since this is our asymmetric center.
00:29
So this can really be trial and error.
00:31
First i'm going to add the bromine.
00:32
We can put it on a bold wedge up here.
00:37
And we know that bromine has a higher priority than chlorine.
00:42
So when we draw our chlorine, we know that we can already see that the arrows will go in a counterclockwise direction.
00:50
And we can also add our hydrogen on a hatched wedge, and that ensures that we don't have to interchange any groups since our lowest priority group is already on a hatched wedge.
00:59
So now we're going to double check, bromine as the highest priority since it is the highest atomic number, followed by chlorine and then our three carbon chain.
01:07
And that all has each of those carbons has hydrogen attached to them too, just they're not drawn.
01:14
And our hydrogen has our lowest priority.
01:16
So we draw arrows from 1 to 2 and 2 to 3.
01:20
Let's go in a counterclockwise direction.
01:23
So we know that that has that configuration and that is drawn correctly.
01:31
Moving on to part b, we have 2r, 3r, 2 .3 dichloropentane.
01:37
Pentane means we have a 5 -carbon chain for our parent chain.
01:41
One, two, three, four, five...