00:01
Okay, so we're going to draw structures and then determine if these structures are optically active.
00:06
Starting first with three bromo hexane.
00:09
So i'm going to start with my hexane.
00:15
I'm going to go to the third carbon, and i'm going to draw my bromon group.
00:20
Okay, so now i'm going to determine if this is optically active.
00:24
And the answer to that is yes, and we can tell that it is because this carbon right here is going to be optically active.
00:32
And we know that because it's bonded to a bromine, a hydrogen, an ethyl, and a propyl.
00:39
Because of that, it's got four distinct groups, and it has a chylosenter.
00:43
So moving on to b, we have three chloro -thre methyl pentane.
00:49
So starting with the pentane.
00:55
Okay.
00:59
So three -chloro -thre methyl, meaning we're going to have three -chloro -thre methyl here.
01:06
Now, this is actually not going to be an optically...