00:01
So this question asks us to draw the following molecules, given the configuration of the chyrocenters.
00:07
So the first thing that i like to do here is draw the parent chain.
00:13
So looking at compound a, we have s to chlorobutane.
00:18
And so i just like to go ahead and draw the butane part of the chain.
00:26
And now we know that we're going to have a two -chloric group in the two position.
00:30
So how do we know whether it's going to be a, a wedged or a dashed line.
00:38
Well, i mean, i kind of like to just kind of draw it as just a solid line, just to kind of envision in my head, whether it's going to be dashed or a wedged.
00:50
So if i were going to think of this line as a wedged, then what i would end up having is our hydrogen group, which is not shown here, is going to be going away from us with a dash, and therefore our configure is going to be exactly as we have it.
01:07
So our chloro would be number one, the ethanol would be number two, and the methyl would be number three.
01:12
And of course, the hydrogen going away from us, which is not shown here, would be number four.
01:16
And so that looks like we'd be going r, right? and that's, in fact, with the configuration where we get.
01:21
However, we want the s.
01:23
And so what's going to end up happening is, instead of our chloro as a wedge, it's actually going to be a dash.
01:32
So it's going to look like this.
01:35
And so our hydrogen will be coming towards us.
01:39
And we can always double -check this absolute configuration as well, right? so we can give our assigned priorities to our groups.
01:47
We know our chloro group is going to be number one because it's the highest mass, and then the alpha group because it's connected to another hydrogen, and then the methyl group because it's connected to three hydrogens.
01:56
And then the hydrogen, of course, is our lowest priority.
01:59
So it looks like here we are going clockwise, which we would normally say r.
02:04
However, we want our largest priority group to be going away from us, which is our hydrogen.
02:11
And so we would just invert stereochemistry here.
02:13
And so we do, in fact, have our s, 2 chlorobutane.
02:18
Okay...