00:05
So t e, cl4, number of balance electrons on this is 6 plus 7 into 4 .34.
00:16
And this is what we subtract from when we do the lewis structure.
00:21
So, cl on all four sides.
00:24
It's obviously going to have electrons, two electrons shared with each cl.
00:30
So 4 into 2, we subtract that out with 26 electrons.
00:36
And then we have to complete the electron octet configuration on all of these co atoms.
00:47
So you have 4 into 6, that's 24.
00:51
So you have two electrons left, which will reside on the tullum.
00:57
So the actual structure would look something like this according to vscpr theory and one electron.
01:07
This is definitely polar because while the dipole moments on these two sides get cancelled out.
01:18
There is a dipole moment from the telurium and chlorides that are not quite balanced.
01:27
So this molecule will be polar.
01:31
Now moving on to the second molecule we have, it's ico5.
01:38
Number of balanced electrons is 7 plus 5 into 7.
01:44
That's 35.
01:45
25 so 42 is what we subtract from.
01:50
Let's write down the 5 cls around iodine.
01:55
It shares two electrons with each molecule.
02:02
So we can subtract that out, so it's 32.
02:06
Then we complete the acted configuration for each of these cl atoms.
02:16
We subtract that out 2, so it's 6 into 5, that's 30, so we have 2 electrons left that will reside on this iodine.
02:22
So if you write it out, then according to the vacpr theory, it will look something like this.
02:28
Cl, cl, cl, cl.
02:33
And then you have the double bond over there.
02:36
So the dipole moments in these four cases will obviously cancel out, but the dipole moment of this chlorine here will not.
02:48
So this will definitely be a polar molecule.
02:57
Moving on to the next atom, sorry molecule that we have.
03:01
It's pcl 5...