Question
Draw the product formed when $(CH_3)_2CHOH$ is treated with each reagent.a. SOCl$_2$ , pyridine b. TsCI, pyridine c. H$_2$SO$_4$d. HBre. PBr$_3$,then NaCN f. POCl$_3$ , pyridine
Step 1
This is due to the fact that SOCl$_2$ is a good chlorinating agent. The reaction is as follows: $$(CH_3)_2CHOH + SOCl_2 \rightarrow (CH_3)_2CHCl + SO_2 + HCl$$ Show more…
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