00:04
This question asks us to draw the products from the reaction of 1 -35 hexatriene, which is this structure with hbr, and then asks us what products will predominate under kinetic control and under thermodynamic control.
00:18
So this is a triene.
00:21
So we're going to do this just like a dying reaction, but instead of just having the 1 -2 and the 1 -4 products here, now we'll have a 1 -6 as well.
00:29
So here, since this is the same on both sides, it doesn't matter which side we start from.
00:34
So i'm just going to start from this side over here.
00:36
We'll call this one and this six.
00:38
So two, three, four, five.
00:40
And our carbocadions are going to be on two, four, and six.
00:44
Normally they're on two and fours.
00:45
So we're just adding the six on because it's the trying.
00:48
So the first step is for the one, two, double bond to grab the hydrogen and we'll kick the bromine off.
00:53
That'll leave us with this bromine nucleophile left over.
00:57
And then the first carbocation that we'll get will look like this.
01:01
It'll be on carbon two.
01:02
The h from the bromine went on to the first carbon over here to allow the carbocadine to be on the more stable carbon right here on carbon 2.
01:11
And then we'll get some resonance here.
01:14
So if we move this like this, we get another resonance contributor of this structure that looks like this.
01:21
So now our carbocadion is over here.
01:24
And then if we move this one more time, we get another structure that looks like this with the carbocatine here on the end.
01:32
So then we can have the bromine nucleophile attack each one of these carbokadines to give us three different products.
01:41
So this first one will be our one -two product and we'll have the bromine here on carbon two.
01:46
So this is one -two...