00:01
This question asks us to draw the products of each of these sn2 reactions.
00:05
So starting with part a, our leaving group here is bromine, and our nucleophile is the methoxide ion.
00:12
So this methoxide ion will come in and do a backside attack on that carbon and push off the bromine.
00:18
So our product will look like this.
00:23
And then for part b, now we have some stereochemistry to consider.
00:28
So remember that sn2 reactions cause an inversion of the stereochemistry because of that backside attack.
00:35
So this will come in here an attack again and push the bromine off, but now we have to consider stereo chemistry.
00:42
So we'll flip the stereochemistry, which means that the bromine was on a wedge.
00:48
So now our oc should be on a dash, and the h will also flip...