00:01
Draw the products of the elimination reactions.
00:03
So we have an alcohol right here.
00:05
Let's make sure we draw on our lone pairs right here.
00:07
Alcohol, and we have an acid.
00:09
This alcohol is going to take hydrogen from this acid.
00:13
Donate there, let's continue drawing.
00:17
Leading to a positively charged water molecule right here, which is then a good leaving group.
00:24
It will then leave our cyclical chain arriving with a carbocat ion right there, this carbon.
00:32
And also giving us a fully formed water molecule right there.
00:36
We love water because water does a lot of stuff.
00:39
Now notice that there is a hydrogen here.
00:43
There's also hydrogen here.
00:45
This water is going to attack one of these hydrogens.
00:49
Which hydrogen will attack? it's going to attack the one.
00:52
It's going to attack this one right here.
00:54
The reason why is because this is the most substituted hydrogen.
00:58
This hydrogen is attached to the, first of all, it's attached to a cyclical area.
01:02
But it's also attached to a carbon that's sps2 versus this top carbon up here.
01:10
This top hydrogen is not as well connected.
01:13
So it's actually less stable to take from this top one.
01:17
So we're going to take from our bottom one.
01:19
Yes here, no there.
01:22
So lachshund pyrr attacks hydrogen, hydrogen donates the bond.
01:26
We have from here the formation of an alken bond.
01:29
This is our most substituted version we want this one.
01:34
This is our substituted, most substituted, most stable product.
01:38
Looking at b...