00:01
Let's draw the products of each proton transfer reaction.
00:05
Starting with our top reaction, what you're going to want to do is look for the strongest acid, meaning the weakest hydrogen, other atom bond.
00:16
And here if we look, the weakest bond is between this oxygen and this hydrogen.
00:21
Therefore, this is going to act as an acid.
00:24
And indeed, this functional group is called a carboxylic acid because it's acidic.
00:28
So therefore, this is going to act as our base.
00:31
If it can and it can it has a negative charge so let's look where the loan pairs are because you're going to have to have a loan pair or a pie bond in order to act as a base.
00:45
So i drew in the loan pairs there.
00:49
Draw again, sorry, and that can attack hydrogen.
00:55
If you attack this hydrogen, it can only have one bond so you have to break one and you break the oxygen -hydrogen bond.
01:02
What that leaves us with is still the trichloral species.
01:08
We didn't make or break any bonds there.
01:10
And now we're left with the carboxylate.
01:13
So a negative charge on that oxygen because you've broken the oxygen -hydrogen bond.
01:19
What's left over is methanol.
01:22
So we had methoxide attack the hydrogen.
01:25
You form methanol.
01:27
This next reaction with acetylene and h -minus.
01:31
H -minus is formally called hydride.
01:35
It is the only lone pair between these two compounds.
01:39
Carbons don't have any lone pairs.
01:41
And it's actually very reactive as a base.
01:44
So the lone pair on hydrogen or hydride could attack, well, either of these two hydrogens...