00:01
So this question asks us to complete this reaction over here.
00:06
The reaction, first reaction with tibotoxide.
00:09
Tipotoxide is a strong base and a bunky, that's why it's a weak nucleophile and that's why it's going to de -protonate and cause the kickoff of the toxicylate group and we end up with an olive in.
00:25
Hbr will react with this old alcohol subsist.
00:30
And generate the bromine product.
00:37
The first step of this one will be the attack of cyanide to the epoxide ring and open the ring protonation with water which generate the product.
00:55
Which should be like this supposedly cyanide attack at either end.
01:05
Oh 99 and cs that 3, 6x3, hydrogen, and in this case hydrogen up, 62, 63.
01:26
All right, this one is a nucleophile and so it will undergo the attack to oxylate as a living group and the mechanism is actually a an sn2, so it's an inversion of chiro center and hydrogen will be up and side and will be down.
01:57
Pbr 3 will promenate and substitute the oh group.
02:03
The mechanism is sn2 and so it will result in the inversion of the chiro center.
02:16
The first step will be t -toxylate, toxic chloride and pyridine will toxylate this alcohol group over here.
02:32
Oh, toxylate, hydrogen, and deuterium...