00:01
So we were taking a look at the products of some different reactions.
00:04
So in the first one here, we do form ananchomas.
00:08
So i will draw out the first enantuma.
00:12
And then in order to get the second, all you need to do is draw the mirror image of this molecule that is on screen.
00:21
So the mirror image would be the ananchima.
00:26
In the second part we have here, again, we have another pair of anachmas.
00:31
So i'll just draw one just to save us a bit of time.
00:36
And then all you need to do is draw the mirror image of this exact molecule to find the enantiuma.
00:48
It's moving on to the side part here.
00:53
We have a six -membered ring, c2h5.
00:58
We also have an alcohol group.
01:01
And then here we have a hydrogen where we do not have any other stereoisimus for this material.
01:07
In the next example, we're moving away from the cyclical molecules.
01:12
And what we have is as follows.
01:18
I have a hydrocarbon chain with some branching.
01:26
Next, what we have is the hydrogenation reaction, which allows us to remove that double bond, and then we have the addition of chlorine as well...