00:01
We have a similar situation as the previous problem, this problem, but now we have loads and the moments are actually in the opposite direction.
00:09
And so we have our forces acting off the beam on kind of l -shaped members causing forces and torques at these c, d, and e.
00:22
We have reaction, it's pinned, so we have reaction forces at f, at a and b, and doing our force and moment.
00:30
Balance on this beam here, we can find that f .a.
00:34
Is 400 newtons and fb is 800 newtons, which makes sense because we have the loads, we have torques basically acting this way so that this load is going to be higher to offset those.
00:51
So we can make our cuts and we start off with four.
00:57
Again, we have uniform shear stresses in each of these regions because we don't have any distributed loads.
01:04
So in this region here, the shear stress is 400 newtons.
01:11
In this region here, it actually drops to zero.
01:17
And here it drops to minus 400, and in this region it drops to minus 800, which is our maximum magnitude...