00:01
In this problem we have a beam that is cannolievered from the left end here.
00:08
And there is a uniformly distributed load acting over part of it.
00:16
And over the first over the left three meters.
00:19
And then a linearly varying distributed load acting over the last one and a half meters.
00:26
Again, replacing these with the equivalent point loads to get the, we can find this reaction force and the reaction moment here.
00:36
The force is 9 kilonutons and the moment is minus 19 .5 kilnought meters.
00:44
Now this function here and again i should make this as a negative since it's in a negative y direction.
00:51
Here goes like the slope is going to be 8 thirds x or the slope is going to be is minus eight thirds.
01:00
So we have, we could find the constant by setting to make sure that this equals zero when x equals four and a half.
01:09
So in this region here, we have the shear force is going to have a slope of minus two.
01:18
It's going to start at nine kilonyms, have a slope of minus two to we get out to here.
01:23
So the function is nine minus two x...