00:01
This question asks us to draw the structural formula for each of the following straight chain alkanes.
00:05
So, for example, a, we have butane, and we know that from the greek but here, sorry, from the greek root, greek prefix.
00:18
So for the but prefix, you know that's going to equal four carbons.
00:27
And so we can go ahead and draw our structural representation here.
00:30
We know that we're going to explicitly draw all the carbon -carbon bonds and all the carbon -hydrogen bonds, and so that it's going to look like the following.
00:41
So we have our carbon -carbon -carbon -carbon chain here, and we know that each of the terminal carbons here on the chain has three other bonds to hydrogens, and all the inside carbons have two other bonds to hydrogens.
01:02
This gives a total of four bonds to each carbon, in order to fulfill its octet rule, because we know that carbon can form a maximum of four bonds.
01:18
Looking at octane, we know that the oct prefix in greek, that refers to eight.
01:27
So we would say oct refers to eight.
01:33
And so we can do the same thing.
01:34
We can draw the structural formula, and that looks like this.
01:45
So we've got to draw our eight carbon -carbon bonds here.
01:50
Three, four, five, six, seven, eight.
01:56
Right, and we know, like, once again, that each of the terminal carbons is going to have three additional bonds to hydrogens, and all the insides are going to have two other bonds, two hydrogens.
02:23
Right...