00:01
Draw the structure corresponding to each name.
00:03
All right, let's try this out.
00:05
So let's break this down.
00:06
So we've got a z, we've got four, ethyl, hept, and three e.
00:13
All right, this tells us quite a bit.
00:14
Let's go ahead and draw.
00:15
So hept is for seven.
00:17
So let's draw seven -carbons.
00:19
One, two, three, four, five, six, seven carbons.
00:26
Now we know that on carbon number, carbon number four, so this is one, this is seven, one, two, three, four.
00:34
This is a number four right here.
00:36
We have an ethyl group.
00:40
And at three, we have an al -keen.
00:45
Now let's draw the meter.
00:47
We have an al -keen.
00:48
Now we do have an orientation given to us, z.
00:51
Z means same.
00:54
We need to have the same priority given to them across the bond.
00:58
So if we were to split this in half, we're going to give priority this carbon because it has a higher atomic number.
01:05
So on the first side, we're going up.
01:07
On the second side, we're going down the longer carbon chains on the bottom, since it's only carbons.
01:13
So this is actually e orientation, which means that we need to flip this a little bit.
01:17
So let's go ahead and redraw this.
01:19
One, two, three, four.
01:22
This is where the alken is.
01:24
We need to flip it.
01:25
So we'll put our ethel group down here.
01:29
We'll put our carbon chain up.
01:32
Up here and that's one two three one two three four just like that and that is now a z for same so this one is good looking at b all right so we've got three five six trimethyl three methyl three methyl groups quite a bit oct for eight and then an alkena two orientation is the opposite so we've got opposite opposite opposite priorities are across that al -keen...