00:01
Hey guys, so in this question, we're asked to find structural formulas for each of these four compounds.
00:07
So in part a, we have 113 trichloro2 propanol.
00:12
So the first thing i'm going to do is i'm going to draw the parent chain, which is prop in this case.
00:19
So that is a three carbon chain.
00:22
And i'm going to use skeletal structural models just because they're more streamlined and easy to see and easier to draw.
00:32
So first thing i'm going to do is draw my parent chain.
00:35
So here's one, two, three carbons.
00:40
Now i'm going to add the hydroxy or the alcohol group on the second carbon, since this is what this two refers to, and it's a ol, so that means it's an alcohol.
00:53
So my oh goes here.
00:56
And i have other substituent.
00:58
So i have three chlorine molecules to attach to my first carbon, so cl here, seal here, and then my last cl is on third carbon.
01:11
So this is my compound for part a.
01:14
Moving on to part b, we have three methyl, three pentamene.
01:19
So the first thing i'm going to do is draw my parent chain, so that's pent.
01:23
So that's a five carbon chain, so one, two, three, four, five.
01:29
Now that i have this, i can go ahead and draw my substituents in.
01:40
So i have an amine group denoted by this amine at 3.
01:46
So i'll draw my nh2 here.
01:52
And i also have a methyl at 3.
01:55
So i'll just draw the methyl right here.
02:00
Actually, i'll use some stereochemistry.
02:02
So i'll have the wedge here denoting that this nh2 is coming out of the page and my methyl here is coming, is behind the page.
02:16
So that's just another way to denote this using stereochemistry denotations.
02:23
So part c, we have three broma, one chloro, two, butanone...