Question
Draw the structure of the following complexes.(a) $f a c$ -bromotrichloro(ethylenediamine) $\operatorname{cobalt}(\mathrm{III})$(b) $c i s$ -dibromotetrachloroferrate $(\mathrm{II})$
Step 1
The formula for this is X + (number of ligands * charge on each ligand) = overall charge on the complex. In this case, we have one bromide ligand with a charge of -1, three chloride ligands with a charge of -1 each, and one ethylenediamine ligand which is neutral. Show more…
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