00:01
This question asks us what kind of product from during a dehydration reaction for these alcohol and if there is a mixture which one will be the major product.
00:12
So in order to do that, first let's take a look at the structure of these molecules.
00:20
So dehydration reaction is the reaction that you're going to eliminate water between the oh alcohol group and the hydrogen and betaposition of the oh.
00:34
So in this case, you have two identical betaposition, and that's why dehydration will find only one product, which is double bond, c -s -3, hydrogen, hydrogen, hydrogen.
00:53
In this case, you have this one, two identical.
01:00
Beta position hydrogen that's going is beta 1 and this is beta 2 so if the dehydration eliminate the oh and the hydrogen in the beta 1 position the product that we're going to have will be so 1 2 3 4 5 1 2 3 4 5 that is beta 1 elimination and if it's happens through beta 2 the product we got we're gonna farm double bun between this and the product in this case will be and so the the major product will be the olivine that has the most the higher substituted olivine and so in this case this one should be a major product because it's a tri -substuted olivine, meanwhile this one is the die -substuted olivine...