Due to a small magnet, intensity at a distance x in the end on position is 9 Gauss. what will be

Name: Problem 1982, Chapter 13: JEE Physics
Uploaded: 2022-01-22T20:05:23-08:00
Duration: 1 min 22 s
Channel: Stephen Zaffke
Description: Due to a small magnet, intensity at a distance x in the end on position is 9 Gauss. what will be the intensity at a distance (x / 2) on broad side on position. (a) 9 Gauss (b) 4 Gauss (c) 36 Gauss (d) 4.5 Gauss A domain in a ferromagnetic s1hh

step 1 Okay, so we have this source of charge right here at point A, and we have points B, C, and D, wh

Question

Due to a small magnet, intensity at a distance $\mathrm{x}$ in the end on position is 9 Gauss. what will be the intensity at a distance $(\mathrm{x} / 2)$ on broad side on position. (a) 9 Gauss (b) 4 Gauss (c) 36 Gauss (d) 4.5 Gauss A domain in a ferromagnetic s1hh

   Due to a small magnet, intensity at a distance $\mathrm{x}$ in the end on position is 9 Gauss. what will be the intensity at a distance $(\mathrm{x} / 2)$ on broad side on position.
(a) 9 Gauss
(b) 4 Gauss
(c) 36 Gauss
(d) 4.5 Gauss A domain in a ferromagnetic s1hh

JEE Physics

StemEZ 1st Edition

Chapter 13, Problem 1982

Instant Answer

Solved by Expert Stephen Zaffke

01/22/2022

Step 1

We know that the intensity of a magnetic field due to a small magnet at a distance x in the end-on position is given by the formula: Intensity (end-on) = μ₀ * m / (4π * x²) where μ₀ is the permeability of free space, m is the magnetic moment of the magnet, Show more…

Show all steps

Thanks for your feedback!

Due to a small magnet, intensity at a distance $\mathrm{x}$ in the end on position is 9 Gauss. what will be the intensity at a distance $(\mathrm{x} / 2)$ on broad side on position. (a) 9 Gauss (b) 4 Gauss (c) 36 Gauss (d) 4.5 Gauss A domain in a ferromagnetic s1hh

Play audio

Feedback

Stephen Zaffke and 71 other subject Physics 102 Electricity and Magnetism educators are ready to help you.

Ask a new question

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Magnetic Dipole Field Distribution

This concept deals with how the magnetic field of a dipole varies depending on the measurement direction relative to its magnetic moment. Specifically, the field measured along the axial (end-on) direction is twice as strong as that measured on the equatorial (broadside) side, due to the inherent geometry of the dipole field lines.

Inverse Cube Law for Magnetic Dipoles

In a magnetic dipole, the field strength decays with the cube of the distance from the dipole. This means that when the distance from the dipole is halved, the magnetic field intensity increases by a factor of eight. When combined with the directional factor (axial versus equatorial), this law is essential for calculating the field intensity at different positions around a dipole.

Please give Ace some feedback