00:01
A car has constant acceleration and reaches a speed 258 .4 miles per hour from rest at a distance 612 .5 meters from the start.
00:10
What was the speed v at 1 fourth, 1ā2nd and 3 fourths this distance? in order to answer this question, we need to have a fundamental understanding of one -dimensional kinematics and what equations are associated with those kinematics.
00:26
So to start off with, let's note what we're given in this problem.
00:29
We're given x -0, x -1, x2, x -3, x4 equals 1 -4th, 1 -4th ,000.
00:34
1 1ā2 4 times 258 .4, or rather 612 .5.
00:41
So x1 is 153 .125 and so on, up to x4 equals 12 .5.
00:46
We want to solve for b1, v2, v3 at x1, x2, x3.
00:51
We're also given v0 equals 0, b4, 258 .4 miles per hour.
00:56
Here, i've used the unit conversion to convert v4 to meters per hour as 415, 800 meters per hour...