Question
During the testing of a new light bulb, a sensor is placed $52.5 \mathrm{~cm}$ from the bulb. It records a root-mean-square value of $9.142 \cdot 10^{-7} \mathrm{~T}$ for the magnetic field of the radiation emitted by the bulb. What is the intensity of that radiation at the sensor's location?
Step 1
We know that 1 meter is equal to 100 centimeters, so we can convert 52.5 centimeters to meters by dividing by 100. This gives us $R = 52.5 \, \text{cm} = 0.525 \, \text{m}$. Show more…
Show all steps
Your feedback will help us improve your experience
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
During the testing of a new light bulb, a sensor is placed $17.7 \mathrm{~cm}$ from the bulb. It records a root-mean-square value of $279.9 \mathrm{~V} / \mathrm{m}$ for the electric field of the radiation emitted from the bulb. What is the intensity of that radiation at the sensor's location?
During the testing of a new light bulb, a sensor is placed $31.9 \mathrm{~cm}$ from the bulb. It records an intensity of $182.9 \mathrm{~W} / \mathrm{m}^{2}$ for the radiation emitted by the bulb. What is the root-mean-square value of the electric field at the sensor's location?
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD